In an ap the sum of first n terms is 5n 2/2
WebJul 12, 2024 · Best answer Let Sn denotes the sum of first n terms of the AP. ∴ Sn = 5n - n2 ⇒ ⇒ Sn-1 = 5 (n - 1) - (n - 1)2 = 5n - 5 - n2 + 2n - 1 = 7n - n2 - 6 ∴ nth term of the AP, an = Sn …
In an ap the sum of first n terms is 5n 2/2
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WebMar 27, 2024 · Solution For 10] Find the sum of first ' n ' terms of an AP 2 ,8 ,18 ,32 , 11] If α,β and γ are the zeroes of the polynomial P(x)=x3−6x2−x+30 then fin. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... WebGiven, the expression for the sum of the series is Sₙ = 3n² + 5n. Last term, l is a k = 164. We have to find the value of k. Put n = 1, S₁ = 3(1)² + 5(1) = 3 + 5 = 8. ... If the sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256, find the sum of th . . . .
WebThe sum of the first n term sofa an AP is ( 3 n 2 2 + 5 n 2). Find its nth term and the 25th term Advertisement Remove all ads Solution Let S denotes the sum of first n terms of the AP. ∴ s n = ( 3 n 2 2 + 5 n 2) ⇒ s n - 1 = 3 ( n - 1) 2 2 + 5 ( n - 1) 2 = 3 ( n 2 - 2 n + 1) 2 + 5 ( n - 1) 2 = 3 n 2 - n - 2 2 ∴ n th term pf the AP , a n WebApr 10, 2024 · Sum of first n terms of an AP S n = n 2 [ 2 a + ( n − 1) d] Where a =1st term & d =common difference Or, S n = n 2 [ a + a n] If there are only n terms in an AP, then a n =l, l=last term We will put n=1, 2 in the sum formula and evaluate the first and second term of the A.P. Then we can easily derive the common difference. By putting all these in
WebJun 4, 2014 · Question 1) Find the sum of the first 24 terms of the list of numbers whose nth term is given (3+2n). Question 2) For what value of n , are the nth terms of the two AP 63,65,67 and 3,10,17..... are equal ? Question 3) The pth term of an AP is a and qth term is b . Prove that the sum of its (p+q) terms = p+q/2{ a+ b+ (a-b/p-q)}. WebIf the nth term of an A.P. is 4n^2 - 5n, what is the sum of the first n term? Given that nth term of an A.P = Note that in any AP, nth term is always linear equation in and cannot be in second degree. However, the sum of first terms of an AP is a second degree equation in .
WebNov 11, 2011 · Find the sum of first n terms if an AP whose nth term is 5n-1. Hence find the sum of first 20 terms Asked by 11 Nov, 2011, 04:16: PM Expert Answer n th term = 5n - 1 Put n=1, we get 1 st term = 5-1 = 4 Hence sum of n terms = n (First term + nth term)/2 = n (4+5n - 1)/2 = n (5n +3)/2 Sum of 20 terms becomes, put n = 20 S 20 = 20 (5×20 +3)/2
WebAug 29, 2024 · If sum to n terms of an A.P. is 5n2 +6n and rth term is 401, then the value of r is Advertisement Expert-Verified Answer 19 people found it helpful Cosmique Answer: Value of r is 40 Explanation: Given, Sum of n terms of an AP is 5 n² + 6 n rth term of AP = aᵣ = 401 To find, Value of r So, Finding the AP damages from hurricane ian 2022WebIn an AP the sum of first n terms is 3n2÷2+5n÷2 then find the 25th term. Solution Let the sum of n terms be given by Sn so Sn = 3n²/2+5n/2 S1 = 3(1)²/2+5(1)/2 = 3/2+5/2= 4 So 1st … birding fanny packWebThe sum of the first n terms of an AP in ( 5 n 2 2 + 3 n 2) .Find its nth term and the 20th term of this AP. Advertisement Remove all ads Solution s n = ( 5 n 2 2 + 3 n 2) = 1 2 ( 5 n 2 + 3 n) ..... (1) Replacing n by (n-1) in (i), we get: s n - 1 = 1 2 × [ 5 ( n - 1) 2 + 3 ( n - 1)] = 1 2 × [ 5 n 2 - 10 n + 5 + 3 n - 3] = 1 2 × [ 5 n 2 - 7 n + 2] damages for wrongful lis pendensWeb(11) Search the sum the first 20 terms of the numerical series in which 3 rl term is 7 also 7 in term is 2 more than three time its 3 rad term. Solution (12) Stylish an arithmetic series, which sum of first 11 conditions is 44 and one that of the next 11 terms is 55. birding falloutWebJun 22, 2024 · According to the given problem The ratio of the sums of first n terms of two A.P.s = (5n+13) : (7n +27 ) = (5n+13) / (7n +27 ) --------------- (4) (3) and (4) are equal. => [2a+ (n-1)d]/ [2b+ (n-1)c] = (5n+13)/ (7n+27) To find ratio of 4 terms , write n = 7 since (2×4-1)=7 => [2a+ (7-1)d]/ [2b+ (7-1)c]= (5 (7)+13))/ (7 (7)+27)) birding experiencesWebAnswer (1 of 3): If a is initial term & d is the common difference, then Sn = { 2a + ( n - 1 ) *d } * n/2 So S2n = { 2a + ( 2n - 1) *d } * n = 2an + 2n^2d - nd = (2a -d)n + 2n^2d = 3n + 14 n^2 Comparing coefficients with terms of n & n^2 we observe 2a - … damages grossing up calculator ukWebIn an A.P the sum of first n terms is 3n2/2 + 13n/2. Find the 25th term arithmetic progression cbse class-10 1 Answer +1 vote answered Sep 30, 2024 by KajalAgarwal (45.2k points) selected Oct 1, 2024 by Vikash Kumar Best answer Given, Sn = 3n2/2 + 13n/2 ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test … damage shaking bass hdd subwoofer